elixir 之 cond 判断 2025-12-02 说明都不支持多 else 匹配条件可以用函数 用法cond12345678910111213141516info1 = ""info2 = ""cond do String.length(info1) !== 0 -> "info1 not 0" String.length(info2) !== 0 -> "info2 not 0" String.length(info1) === 0 && String.length(info2) === 0 -> "len are 0" true -> "default"end if12345if String.valid?("aaa") && String.valid?("bbb") do "Valid string!"else "Invalid string."end